Please attempt the questions before reading these answers!
Q1
1.1. \(\alpha\) is the \(y\)-intercept of the regression line \(\mathbb{E}(Y) = \alpha + \beta x\).
1.2. \(\beta\) is the gradient of the regression line \(\mathbb{E}(Y) = \alpha + \beta x\).
Q2
2.1. A residual is the difference between the observed value \(y_i\) and the estimated value \(\mathbb{E}(Y_{i})\).
2.2. It minimizes the squared sum of the residuals to find the optimal regression line for a sample of data.
Q3
3.1. Here, \(\hat{\alpha} = 146.6853\).
3.2. Here, \(\hat{\beta} = 1.7044\).
3.3. \(\mathbb{E}(Y) = \alpha + \beta x = \hat{\alpha} + \hat{\beta} x = 146.6853 + 1.7044 x\)
3.4. The \(R^2\) coefficient of determination is \(0.2691\), which suggests that the response variable is not well modelled by a linear model of the explanatory variable.
Please note that for this question, the following R code was used. It is recommended that you use Calculator: Simple linear regression or statistical software like this to do these calculations, as these can be very tedious to do by hand.
confectionery =data.frame(customers=c(43,54,65,42,68,49, 63,57,71,47,75,67),sweets=c(188,197,215,217,233,244,254,256,274,286,291,300))model=lm(sweets~customers,data=confectionery)summary(model)plot(confectionery$customers, confectionery$sweets,pch =19, col ="#3f68b6",xlab ="Number of customers",ylab ="Sweets sold")abline(model, col ="#db4315", lwd =2)
Code output:
Call:
lm(formula = sweets ~ customers, data = confectionery)
Residuals:
Min 1Q Median 3Q Max
-42.471 -30.181 3.121 14.471 59.208
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 146.6853 52.7694 2.780 0.0195 *
customers 1.7044 0.8882 1.919 0.0839 .
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Residual standard error: 33.36 on 10 degrees of freedom
Multiple R-squared: 0.2691, Adjusted R-squared: 0.1961
F-statistic: 3.683 on 1 and 10 DF, p-value: 0.08395
Version history and licensing
v1.0: initial version created 12/25 by Flora Green as part of a University of St Andrews VIP project.
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